A can finish a work in 12 days and B can do it in 15 days. After A had worked for 3 days, B also joined A to finish the remaining work. In how many days the remaining work will be finished?
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Solution
work done by A in 3 days = 3× =
Remaining work =
Now, (A and B)'s 1 day's work =
∴ 1 : : : : x ⇒ = 5
2 men undertake to do a job for Rs. 1400. One can do it alone in 7 days and the other in 8 days. With the assistance of a boy they finish the work in 3 days. How should the money be divided?
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Solution
Let the boy completes the work in x days, thus according to the condition
∴ x = Days.
So, money is to be shared in the ratio
Thus, A’s amount = = Rs. 600
B's amount = = 525
Boy's amount = = Rs. 275
A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work they can finish in a day?
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Solution
A’s 1 day’s work = and B's 1 day's work =
∴ (A+B)'s 1 day's work = =
X and Y can do a job in 2 days. If X alone can do the same job in 6 days. How many days will be taken by Y to do the job alone?
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Solution
(X + Y)’s one day’s work =
X’s one day’s work =
Y’s one day’s work =
∴ Y alone can complete the work in 3 days.
24 men complete a given job in 40 days. The number of men required to complete the job in 32 days is
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Solution
Let x be the number of required men to complete the work.
∴ 32 : 40 : : 24 : x
⇒
Four taps can individually fill a cistern of water in 1 h, 2, h, 3 h, and 6 h, respectively. If all the four taps are opened simultaneously, the cistern can be filled in how many minutes?
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Solution
Required time =
A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work?
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Solution
A’s 1 day’s work = and B's 1 day's work = .
∴ (A + B)’s 1 day’s work =
So, both together will finish the work in 6 days.
Shyam can finish a piece of work in 12 days while Rajesh can do it in 20 days. In how many days will they complete the work together ?
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Solution
hyam’s one day’s work =
Rajesh’s one day’s work =
∴ One’s day’s work of both =
∴ Time taken by both to finish the work = days
X can do a piece of work in 24 days. If Y is 60% more efficient than X, then Y can complete the work in
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Solution
X’s one day’s work =
∴ Y's one day's work = 160% of
∴ Y will take 15 days to finish the work
A can do of a work in 12 days. In how many days A can finish the work?
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Solution
∵ A can do of work in 12 days
∴ A can do work in days
∴ A can do work in = 8 days