What will be the least number of square tiles required to pave a hall of length 15 m 17 cm and 9 m 2 cm ?
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Solution
Size of square tiles = HCF of 1517 and 902 = 41 cm
So number of tiles =
The HCF and LCM of number and will be
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Solution
HCF of and =
LCM of = 140
What must be subtracted from 1300 so that the number when divided by 9, 11 and 13 will leave in each case the remainder ’10’.
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Solution
LCM of 9, 11 and 13 = 1287
So number will be 1287 + 10 = 1297
Required number to be subtracted = 1300-1297 = 3
Find sum of the numbers between 300 and 400, such that when they are divided by 6, 9 and 12 leaves 4 as a remainder in each case.
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Solution
LCM of (6, 9, 12) = 36
So numbers will be (324 + 4 ) + (360 + 4) = 692
Three persons start running around a circular track. They complete their respective round in 27 seconds, 45 seconds and 54 seconds. If they start together then after how much time they will meet at starting point together.
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Solution
The required time = LCM of (27, 45 and 54) = 270 seconds
= 4 minute 30 second
= minutes.
The greatest number that will divide 148, 186 and 246 leaving the remainder 4, 6, 6 respectively.
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Solution
The required number = HCF of [148-4, 186-6, 246-6]
= HCF of [144, 180 and 240]
= 12
Find the HCF of terms 1.2, 0.36, 0.48, 0.72 and 2.4
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Solution
Converting into integers.
120, 36, 48, 72 and 240
So HCF of term = 12.
Required HCF. of terms = 0.12
Three bells rings at a interval of 36, 72 and 144 seconds respectively, if they commenced at 12 : 30 pm together then next time they will commence together at ?
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Solution
L.C.M. of (36, 72 and 144)
= 144 seconds = 2 minute 24 second.
⇒ Next time = 12 : 30 + 00 : 02 : 34
= 12 : 32 : 24 PM
The H.C.F and L.C.M of two numbers are 44 and 264 Respectively. If the first number is divided by 8 quotient is 11. The second number is.
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Solution
HCF = 44 LCM = 264
First number = 8 × 11 = 88
Second number = = 132
The LCM of terms and will be.
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Solution
LCM of and
= LCM of 9 and 18 = 18