A man, a woman and a boy can complete a work in 20, 30, and 60 days respectively. Then find the number of boys required to assist 2 men and 8 women so that the work could be completed in 2 days?
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Solution
2 men's 2 days work ⇒
8 women's 2 days work ⇒
x Boy's 2 days work ⇒
So ⇒
⇒
⇒ x = 30 – 22 = 8 boys.
A completes a work in 10 days while with B , he can complete the same amount of work in 5 days. Then ratio of their working capacity is :
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Solution
B will complete the work in = days
So Ratio of efficiency ⇒
⇒ 1 : 1
A completes a work in 9 days while B competes the same work in 18 days. If they together complete the work then what fraction of work is completed by A ?
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Solution
A's 1 day work =
B's 1 day work =
Then A is twice as efficient as B is ⇒
A is twice as efficient as B , who is twice as efficient as C. if A and B together complete a work in 4 days then number of days required to complete the work by C is :
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Solution
Let A complete the work in x days
Then B will complete → 2x days.
and C will complete → 4x days.
Given →
⇒
⇒ 2x = 12
⇒ x = 6
Then C will complete in → 6 × 4 = 24 days.
A is thrice as efficient as B hence takes 60 days less to complete a work. find the number of days to complete the work if they work together?
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Solution
let B takes x days to complete the work then A will take (x – 60) days to complete the work
B's one day work = , A's one day work =
(A+B)'s one day work =
so number of required days or days.
To complete a work A takes twice as much time as B takes, while C takes thrice as much time as B takes. working together they can complete the work in 12 days. Find the number of days in which A alone can compete the work ?
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Solution
let B takes x days to complete the work
∴ A's time = 2x days
and C's time = 3x days
so (A + B + C) will complete work in a day ⇒
x = 22
∴ A will take = 2x = 2 × 22 = 44 days to complete the work
A man, a woman, and a boy together can complete a work in 3 days. if a man can complete it in 6 days while a boy can complete it in 18 days then find the number of days in which a woman can complete the same work?
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Solution
(1 man + 1 woman + 1 boy)'s one day work =
1 man's one day work = , a boy's one day work =
then 1 woman's one day work =
so a woman will complete the work in 9 days.
The working capacity of A is half of B and working capacity of C is half of A and B’s together. If C completes a work in 20 days then find the number of days in which all three can complete the work ?
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Solution
C can complete a work in 20 days.
according to question (A + B) complete the work in = days
then (A + B + C) will complete the work =
days
A alone can complete a work in 16 days and B alone can complete the same work in 12 days. If C with the help of A and B can complete it in 4 days then C alone can complete the work in _ days.
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Solution
A's one day work = , B 's one day work =
(A + B + C) 's one day work =
∴ C's one day work =
so C will complete the work in days= days
A and B together can complete a work in 72 days, B and C in 120 days , C and A can complete the same work in 90 days. Find the number of days in which A alone can complete the work?
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Solution
(A + B + C)'s one day work =
∴ (A + B + C) – (B + C) =
A's one day work = days
So A can complete the work in 120 days